6(u-1)-1=-5(-6u+2)-9u=

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Solution for 6(u-1)-1=-5(-6u+2)-9u= equation: 



6(u-1)-1=-5(-6u+2)-9u=

We move all terms to the left:

6(u-1)-1-(-5(-6u+2)-9u)=0

We multiply parentheses

6u-(-5(-6u+2)-9u)-6-1=0



We calculate terms in parentheses: -(-5(-6u+2)-9u), so:

-5(-6u+2)-9u

We add all the numbers together, and all the variables

-9u-5(-6u+2)

We multiply parentheses

-9u+30u-10

We add all the numbers together, and all the variables

21u-10

Back to the equation:

-(21u-10)



We add all the numbers together, and all the variables

6u-(21u-10)-7=0

We get rid of parentheses

6u-21u+10-7=0

We add all the numbers together, and all the variables

-15u+3=0

We move all terms containing u to the left, all other terms to the right

-15u=-3

u=-3/-15

u=1/5

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