4(2v+1)-5(v-2)=8

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Solution for 4(2v+1)-5(v-2)=8 equation: 



4(2v+1)-5(v-2)=8

We move all terms to the left:

4(2v+1)-5(v-2)-(8)=0

We multiply parentheses

8v-5v+4+10-8=0

We add all the numbers together, and all the variables

3v+6=0

We move all terms containing v to the left, all other terms to the right

3v=-6

v=-6/3

v=-2

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