18(v+4)-2v=4(4v+4)-22

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Solution for 18(v+4)-2v=4(4v+4)-22 equation:



18(v+4)-2v=4(4v+4)-22
We move all terms to the left:
18(v+4)-2v-(4(4v+4)-22)=0
We add all the numbers together, and all the variables
-2v+18(v+4)-(4(4v+4)-22)=0
We multiply parentheses
-2v+18v-(4(4v+4)-22)+72=0
We calculate terms in parentheses: -(4(4v+4)-22), so:
4(4v+4)-22
We multiply parentheses
16v+16-22
We add all the numbers together, and all the variables
16v-6
Back to the equation:
-(16v-6)
We add all the numbers together, and all the variables
16v-(16v-6)+72=0
We get rid of parentheses
16v-16v+6+72=0
We add all the numbers together, and all the variables
78!=0
There is no solution for this equation

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