4(2t-4)+3t=32+t

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Solution for 4(2t-4)+3t=32+t equation: 



4(2t-4)+3t=32+t

We move all terms to the left:

4(2t-4)+3t-(32+t)=0

We add all the numbers together, and all the variables

4(2t-4)+3t-(t+32)=0

We add all the numbers together, and all the variables

3t+4(2t-4)-(t+32)=0

We multiply parentheses

3t+8t-(t+32)-16=0

We get rid of parentheses

3t+8t-t-32-16=0

We add all the numbers together, and all the variables

10t-48=0

We move all terms containing t to the left, all other terms to the right

10t=48

t=48/10

t=4+4/5

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