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x(x-3)=x2+6x+5
We move all terms to the left:
x(x-3)-(x2+6x+5)=0
We add all the numbers together, and all the variables
-(+x^2+6x+5)+x(x-3)=0
We multiply parentheses
-(+x^2+6x+5)+x^2-3x=0
We get rid of parentheses
-x^2+x^2-6x-3x-5=0
We add all the numbers together, and all the variables
-9x-5=0
We move all terms containing x to the left, all other terms to the right
-9x=5
x=5/-9
x=-5/9
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