4(2n-2)=(4n+7)+8

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Solution for 4(2n-2)=(4n+7)+8 equation: 



4(2n-2)=(4n+7)+8

We move all terms to the left:

4(2n-2)-((4n+7)+8)=0

We multiply parentheses

8n-((4n+7)+8)-8=0



We calculate terms in parentheses: -((4n+7)+8), so:

(4n+7)+8

We get rid of parentheses

4n+7+8

We add all the numbers together, and all the variables

4n+15

Back to the equation:

-(4n+15)



We get rid of parentheses

8n-4n-15-8=0

We add all the numbers together, and all the variables

4n-23=0

We move all terms containing n to the left, all other terms to the right

4n=23

n=23/4

n=5+3/4

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