3x+-(2x+5)=19+4(x-6)

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Solution for 3x+-(2x+5)=19+4(x-6) equation: 



3x+-(2x+5)=19+4(x-6)

We move all terms to the left:

3x+-(2x+5)-(19+4(x-6))=0

We add all the numbers together, and all the variables

3x-(2x+5)-(19+4(x-6))=0

We get rid of parentheses

3x-2x-(19+4(x-6))-5=0



We calculate terms in parentheses: -(19+4(x-6)), so:

19+4(x-6)

determiningTheFunctionDomain
4(x-6)+19

We multiply parentheses

4x-24+19

We add all the numbers together, and all the variables

4x-5

Back to the equation:

-(4x-5)



We add all the numbers together, and all the variables

x-(4x-5)-5=0

We get rid of parentheses

x-4x+5-5=0

We add all the numbers together, and all the variables

-3x=0

x=0/-3

x=0

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