4(2n+3)=31-(n-1)

Solution for 4(2n+3)=31-(n-1) equation:

4(2n+3)=31-(n-1)

We move all terms to the left:

4(2n+3)-(31-(n-1))=0

We multiply parentheses

8n-(31-(n-1))+12=0


We calculate terms in parentheses: -(31-(n-1)), so:

31-(n-1)

determiningTheFunctionDomain
-(n-1)+31

We get rid of parentheses

-n+1+31

We add all the numbers together, and all the variables

-1n+32

Back to the equation:

-(-1n+32)


We get rid of parentheses

8n+1n-32+12=0

We add all the numbers together, and all the variables

9n-20=0

We move all terms containing n to the left, all other terms to the right

9n=20

n=20/9

n=2+2/9