13*((49+11x)/9)-12x=63

Solution for 13*((49+11x)/9)-12x=63 equation:

13((49+11x)/9)-12x=63

We move all terms to the left:

13((49+11x)/9)-12x-(63)=0

We add all the numbers together, and all the variables

13((11x+49)/9)-12x-63=0

We add all the numbers together, and all the variables

-12x+13((11x+49)/9)-63=0

We multiply all the terms by the denominator


-12x*9)+13((11x+49)-63*9)=0

We add all the numbers together, and all the variables

-12x*9)+13((11x+49)=0

Wy multiply elements

-108x^2=0

a = -108; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-108)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{-216}=0$