4(2n+3)=-3(n-1)+31

Solution for 4(2n+3)=-3(n-1)+31 equation:

4(2n+3)=-3(n-1)+31

We move all terms to the left:

4(2n+3)-(-3(n-1)+31)=0

We multiply parentheses

8n-(-3(n-1)+31)+12=0


We calculate terms in parentheses: -(-3(n-1)+31), so:

-3(n-1)+31

We multiply parentheses

-3n+3+31

We add all the numbers together, and all the variables

-3n+34

Back to the equation:

-(-3n+34)


We get rid of parentheses

8n+3n-34+12=0

We add all the numbers together, and all the variables

11n-22=0

We move all terms containing n to the left, all other terms to the right

11n=22

n=22/11

n=2