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5x-(x+2)=3(x+5)+2
We move all terms to the left:
5x-(x+2)-(3(x+5)+2)=0
We get rid of parentheses
5x-x-(3(x+5)+2)-2=0
We calculate terms in parentheses: -(3(x+5)+2), so:We add all the numbers together, and all the variables
3(x+5)+2
We multiply parentheses
3x+15+2
We add all the numbers together, and all the variables
3x+17
Back to the equation:
-(3x+17)
4x-(3x+17)-2=0
We get rid of parentheses
4x-3x-17-2=0
We add all the numbers together, and all the variables
x-19=0
We move all terms containing x to the left, all other terms to the right
x=19
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