4(2n+1)=32

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Solution for 4(2n+1)=32 equation: 



4(2n+1)=32

We move all terms to the left:

4(2n+1)-(32)=0

We multiply parentheses

8n+4-32=0

We add all the numbers together, and all the variables

8n-28=0

We move all terms containing n to the left, all other terms to the right

8n=28

n=28/8

n=3+1/2

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