4(2m+1)=3(m-2)

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Solution for 4(2m+1)=3(m-2) equation: 



4(2m+1)=3(m-2)

We move all terms to the left:

4(2m+1)-(3(m-2))=0

We multiply parentheses

8m-(3(m-2))+4=0



We calculate terms in parentheses: -(3(m-2)), so:

3(m-2)

We multiply parentheses

3m-6

Back to the equation:

-(3m-6)



We get rid of parentheses

8m-3m+6+4=0

We add all the numbers together, and all the variables

5m+10=0

We move all terms containing m to the left, all other terms to the right

5m=-10

m=-10/5

m=-2

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