(3x-5)4x+12=1

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Solution for (3x-5)4x+12=1 equation: 



(3x-5)4x+12=1

We move all terms to the left:

(3x-5)4x+12-(1)=0

We add all the numbers together, and all the variables

(3x-5)4x+11=0

We multiply parentheses

12x^2-20x+11=0

a = 12; b = -20; c = +11;
Δ = b2-4ac
Δ = -202-4·12·11
Δ = -128
Delta is less than zero, so there is no solution for the equation

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