4(2g-3)-5(g-12)=33

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Solution for 4(2g-3)-5(g-12)=33 equation: 



4(2g-3)-5(g-12)=33

We move all terms to the left:

4(2g-3)-5(g-12)-(33)=0

We multiply parentheses

8g-5g-12+60-33=0

We add all the numbers together, and all the variables

3g+15=0

We move all terms containing g to the left, all other terms to the right

3g=-15

g=-15/3

g=-5

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