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5y+4=2(y+3)+1
We move all terms to the left:
5y+4-(2(y+3)+1)=0
We calculate terms in parentheses: -(2(y+3)+1), so:We get rid of parentheses
2(y+3)+1
We multiply parentheses
2y+6+1
We add all the numbers together, and all the variables
2y+7
Back to the equation:
-(2y+7)
5y-2y-7+4=0
We add all the numbers together, and all the variables
3y-3=0
We move all terms containing y to the left, all other terms to the right
3y=3
y=3/3
y=1
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