4(2c-8)=-10+2(2c+1)

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Solution for 4(2c-8)=-10+2(2c+1) equation: 



4(2c-8)=-10+2(2c+1)

We move all terms to the left:

4(2c-8)-(-10+2(2c+1))=0

We multiply parentheses

8c-(-10+2(2c+1))-32=0



We calculate terms in parentheses: -(-10+2(2c+1)), so:

-10+2(2c+1)

determiningTheFunctionDomain
2(2c+1)-10

We multiply parentheses

4c+2-10

We add all the numbers together, and all the variables

4c-8

Back to the equation:

-(4c-8)



We get rid of parentheses

8c-4c+8-32=0

We add all the numbers together, and all the variables

4c-24=0

We move all terms containing c to the left, all other terms to the right

4c=24

c=24/4

c=6

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