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m2-7m-10=0
We add all the numbers together, and all the variables
m^2-7m-10=0
a = 1; b = -7; c = -10;
Δ = b2-4ac
Δ = -72-4·1·(-10)
Δ = 89
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-7)-\sqrt{89}}{2*1}=\frac{7-\sqrt{89}}{2} $$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-7)+\sqrt{89}}{2*1}=\frac{7+\sqrt{89}}{2} $
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