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4(2a+8)a=-4
We move all terms to the left:
4(2a+8)a-(-4)=0
We add all the numbers together, and all the variables
4(2a+8)a+4=0
We multiply parentheses
8a^2+32a+4=0
a = 8; b = 32; c = +4;
Δ = b2-4ac
Δ = 322-4·8·4
Δ = 896
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{896}=\sqrt{64*14}=\sqrt{64}*\sqrt{14}=8\sqrt{14}$$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(32)-8\sqrt{14}}{2*8}=\frac{-32-8\sqrt{14}}{16} $$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(32)+8\sqrt{14}}{2*8}=\frac{-32+8\sqrt{14}}{16} $
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