9j-(5j+1)-(2+8j-(7j-5))+9j=0

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Solution for 9j-(5j+1)-(2+8j-(7j-5))+9j=0 equation: 



9j-(5j+1)-(2+8j-(7j-5))+9j=0

We add all the numbers together, and all the variables

18j-(5j+1)-(2+8j-(7j-5))=0

We get rid of parentheses

18j-5j-(2+8j-(7j-5))-1=0



We calculate terms in parentheses: -(2+8j-(7j-5)), so:

2+8j-(7j-5)

determiningTheFunctionDomain
8j-(7j-5)+2

We get rid of parentheses

8j-7j+5+2

We add all the numbers together, and all the variables

j+7

Back to the equation:

-(j+7)



We add all the numbers together, and all the variables

13j-(j+7)-1=0

We get rid of parentheses

13j-j-7-1=0

We add all the numbers together, and all the variables

12j-8=0

We move all terms containing j to the left, all other terms to the right

12j=8

j=8/12

j=2/3

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