4(20+2x)=38+2x

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Solution for 4(20+2x)=38+2x equation: 



4(20+2x)=38+2x

We move all terms to the left:

4(20+2x)-(38+2x)=0

We add all the numbers together, and all the variables

4(2x+20)-(2x+38)=0

We multiply parentheses

8x-(2x+38)+80=0

We get rid of parentheses

8x-2x-38+80=0

We add all the numbers together, and all the variables

6x+42=0

We move all terms containing x to the left, all other terms to the right

6x=-42

x=-42/6

x=-7

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