2-(1+6b)=6(1-b)-5

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Solution for 2-(1+6b)=6(1-b)-5 equation: 



2-(1+6b)=6(1-b)-5

We move all terms to the left:

2-(1+6b)-(6(1-b)-5)=0

We add all the numbers together, and all the variables

-(6b+1)-(6(-1b+1)-5)+2=0

We get rid of parentheses

-6b-(6(-1b+1)-5)-1+2=0



We calculate terms in parentheses: -(6(-1b+1)-5), so:

6(-1b+1)-5

We multiply parentheses

-6b+6-5

We add all the numbers together, and all the variables

-6b+1

Back to the equation:

-(-6b+1)



We add all the numbers together, and all the variables

-6b-(-6b+1)+1=0

We get rid of parentheses

-6b+6b-1+1=0

We add all the numbers together, and all the variables

=0

b=0/1

b=0

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