4(2-n)=3(n-5)

Solution for 4(2-n)=3(n-5) equation:

4(2-n)=3(n-5)

We move all terms to the left:

4(2-n)-(3(n-5))=0

We add all the numbers together, and all the variables

4(-1n+2)-(3(n-5))=0

We multiply parentheses

-4n-(3(n-5))+8=0


We calculate terms in parentheses: -(3(n-5)), so:

3(n-5)

We multiply parentheses

3n-15

Back to the equation:

-(3n-15)


We get rid of parentheses

-4n-3n+15+8=0

We add all the numbers together, and all the variables

-7n+23=0

We move all terms containing n to the left, all other terms to the right

-7n=-23

n=-23/-7

n=3+2/7