4(2-b)+3+2b=33

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Solution for 4(2-b)+3+2b=33 equation: 



4(2-b)+3+2b=33

We move all terms to the left:

4(2-b)+3+2b-(33)=0

We add all the numbers together, and all the variables

4(-1b+2)+2b+3-33=0

We add all the numbers together, and all the variables

2b+4(-1b+2)-30=0

We multiply parentheses

2b-4b+8-30=0

We add all the numbers together, and all the variables

-2b-22=0

We move all terms containing b to the left, all other terms to the right

-2b=22

b=22/-2

b=-11

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