(5/(x+2))-(3/(x+1))+4=0

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Solution for (5/(x+2))-(3/(x+1))+4=0 equation: 



(5/(x+2))-(3/(x+1))+4=0



Domain of the equation: (x+2))!=0

x∈R





Domain of the equation: (x+1))!=0

x∈R



We calculate fractions


(5x+5)/((x+2))*x+(-3x-6)/((x+2))*x+4=0

We multiply all the terms by the denominator


(5x+5)+(-3x-6)+4*((x+2))*x=0

We get rid of parentheses

5x-3x+4*((x+2))*x+5-6=0

We add all the numbers together, and all the variables

2x+4*((x+2))*x-1=0

We move all terms containing x to the left, all other terms to the right

2x+4*((x+2))*x=1

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