4(2-8(4c-7))=12(1-13c)-4

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Solution for 4(2-8(4c-7))=12(1-13c)-4 equation: 



4(2-8(4c-7))=12(1-13c)-4

We move all terms to the left:

4(2-8(4c-7))-(12(1-13c)-4)=0

We add all the numbers together, and all the variables

4(2-8(4c-7))-(12(-13c+1)-4)=0



We calculate terms in parentheses: -(12(-13c+1)-4), so:

12(-13c+1)-4

We multiply parentheses

-156c+12-4

We add all the numbers together, and all the variables

-156c+8

Back to the equation:

-(-156c+8)



We get rid of parentheses

4(2-8(4c-7))+156c-8=0

We add all the numbers together, and all the variables

156c+4(2-8(4c-7))-8=0

We move all terms containing c to the left, all other terms to the right

156c+4(2-8(4c-7))=8

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