2x-4/x=1-3x/x

Solution for 2x-4/x=1-3x/x equation:

2x-4/x=1-3x/x

We move all terms to the left:

2x-4/x-(1-3x/x)=0


Domain of the equation: x!=0

x∈R



Domain of the equation: x)!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

2x-4/x-(-3x/x+1)=0

We get rid of parentheses

2x-4/x+3x/x-1=0

We multiply all the terms by the denominator


2x*x+3x-1*x-4=0

We add all the numbers together, and all the variables

2x+2x*x-4=0

Wy multiply elements

2x^2+2x-4=0

a = 2; b = 2; c = -4;
Δ = b2-4ac
Δ = 22-4·2·(-4)
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{36}=6$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-6}{2*2}=\frac{-8}{4}
=-2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+6}{2*2}=\frac{4}{4}
=1
$