4(2-4x)3x=63

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Solution for 4(2-4x)3x=63 equation: 



4(2-4x)3x=63

We move all terms to the left:

4(2-4x)3x-(63)=0

We add all the numbers together, and all the variables

4(-4x+2)3x-63=0

We multiply parentheses

-48x^2+24x-63=0

a = -48; b = 24; c = -63;
Δ = b2-4ac
Δ = 242-4·(-48)·(-63)
Δ = -11520
Delta is less than zero, so there is no solution for the equation

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