6(x+2)=2(-x+10)

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Solution for 6(x+2)=2(-x+10) equation: 



6(x+2)=2(-x+10)

We move all terms to the left:

6(x+2)-(2(-x+10))=0

We add all the numbers together, and all the variables

6(x+2)-(2(-1x+10))=0

We multiply parentheses

6x-(2(-1x+10))+12=0



We calculate terms in parentheses: -(2(-1x+10)), so:

2(-1x+10)

We multiply parentheses

-2x+20

Back to the equation:

-(-2x+20)



We get rid of parentheses

6x+2x-20+12=0

We add all the numbers together, and all the variables

8x-8=0

We move all terms containing x to the left, all other terms to the right

8x=8

x=8/8

x=1

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