4(18a-7)+40=3(4+2a)

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Solution for 4(18a-7)+40=3(4+2a) equation: 



4(18a-7)+40=3(4+2a)

We move all terms to the left:

4(18a-7)+40-(3(4+2a))=0

We add all the numbers together, and all the variables

4(18a-7)-(3(2a+4))+40=0

We multiply parentheses

72a-(3(2a+4))-28+40=0



We calculate terms in parentheses: -(3(2a+4)), so:

3(2a+4)

We multiply parentheses

6a+12

Back to the equation:

-(6a+12)



We add all the numbers together, and all the variables

72a-(6a+12)+12=0

We get rid of parentheses

72a-6a-12+12=0

We add all the numbers together, and all the variables

66a=0

a=0/66

a=0

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