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3(x-6)-8x=2+5(2x+2)
We move all terms to the left:
3(x-6)-8x-(2+5(2x+2))=0
We add all the numbers together, and all the variables
-8x+3(x-6)-(2+5(2x+2))=0
We multiply parentheses
-8x+3x-(2+5(2x+2))-18=0
We calculate terms in parentheses: -(2+5(2x+2)), so:We add all the numbers together, and all the variables
2+5(2x+2)
determiningTheFunctionDomain 5(2x+2)+2
We multiply parentheses
10x+10+2
We add all the numbers together, and all the variables
10x+12
Back to the equation:
-(10x+12)
-5x-(10x+12)-18=0
We get rid of parentheses
-5x-10x-12-18=0
We add all the numbers together, and all the variables
-15x-30=0
We move all terms containing x to the left, all other terms to the right
-15x=30
x=30/-15
x=-2
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