4(10x-2)=6(2x+22)

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Solution for 4(10x-2)=6(2x+22) equation: 



4(10x-2)=6(2x+22)

We move all terms to the left:

4(10x-2)-(6(2x+22))=0

We multiply parentheses

40x-(6(2x+22))-8=0



We calculate terms in parentheses: -(6(2x+22)), so:

6(2x+22)

We multiply parentheses

12x+132

Back to the equation:

-(12x+132)



We get rid of parentheses

40x-12x-132-8=0

We add all the numbers together, and all the variables

28x-140=0

We move all terms containing x to the left, all other terms to the right

28x=140

x=140/28

x=5

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