4(1/8+2)=2(t-8)-1/2t

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Solution for 4(1/8+2)=2(t-8)-1/2t equation: 



4(1/8+2)=2(t-8)-1/2t

We move all terms to the left:

4(1/8+2)-(2(t-8)-1/2t)=0



Domain of the equation: 2t)!=0

t!=0/1

t!=0

t∈R



We multiply parentheses

-(2(t-8)-1/2t)+8+1/8*4=0

We calculate fractions


(-(2(t-8)-1*8*4)/2t*8*4)+2t/2t*8*4)+8=0



We calculate terms in parentheses: +(-(2(t-8)-1*8*4)/2t*8*4), so:

-(2(t-8)-1*8*4)/2t*8*4

We multiply all the terms by the denominator


-(2(t-8)-1*8*4)



We calculate terms in parentheses: -(2(t-8)-1*8*4), so:

2(t-8)-1*8*4

We add all the numbers together, and all the variables

2(t-8)-32

We multiply parentheses

2t-16-32

We add all the numbers together, and all the variables

2t-48

Back to the equation:

-(2t-48)



We get rid of parentheses

-2t+48

Back to the equation:

+(-2t+48)



We get rid of parentheses

-2t+2t/2t*8*4)+8+48=0

We multiply all the terms by the denominator


-2t*2t*8*4)+8+48+2t=0

Wy multiply elements

-128t^3*8=0

We do not support etpression: t^3

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