3x+5=17+2(x-1)

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Solution for 3x+5=17+2(x-1) equation: 



3x+5=17+2(x-1)

We move all terms to the left:

3x+5-(17+2(x-1))=0



We calculate terms in parentheses: -(17+2(x-1)), so:

17+2(x-1)

determiningTheFunctionDomain
2(x-1)+17

We multiply parentheses

2x-2+17

We add all the numbers together, and all the variables

2x+15

Back to the equation:

-(2x+15)



We get rid of parentheses

3x-2x-15+5=0

We add all the numbers together, and all the variables

x-10=0

We move all terms containing x to the left, all other terms to the right

x=10

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