4(1-b)+36=-2(b+1)

Solution for 4(1-b)+36=-2(b+1) equation:

4(1-b)+36=-2(b+1)

We move all terms to the left:

4(1-b)+36-(-2(b+1))=0

We add all the numbers together, and all the variables

4(-1b+1)-(-2(b+1))+36=0

We multiply parentheses

-4b-(-2(b+1))+4+36=0


We calculate terms in parentheses: -(-2(b+1)), so:

-2(b+1)

We multiply parentheses

-2b-2

Back to the equation:

-(-2b-2)


We add all the numbers together, and all the variables

-4b-(-2b-2)+40=0

We get rid of parentheses

-4b+2b+2+40=0

We add all the numbers together, and all the variables

-2b+42=0

We move all terms containing b to the left, all other terms to the right

-2b=-42

b=-42/-2

b=+21