8(2x+1)=-40

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Solution for 8(2x+1)=-40 equation: 



8(2x+1)=-40

We move all terms to the left:

8(2x+1)-(-40)=0

We add all the numbers together, and all the variables

8(2x+1)+40=0

We multiply parentheses

16x+8+40=0

We add all the numbers together, and all the variables

16x+48=0

We move all terms containing x to the left, all other terms to the right

16x=-48

x=-48/16

x=-3

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