4(1+a)-6a=-1-5(7-2a)

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Solution for 4(1+a)-6a=-1-5(7-2a) equation:



4(1+a)-6a=-1-5(7-2a)
We move all terms to the left:
4(1+a)-6a-(-1-5(7-2a))=0
We add all the numbers together, and all the variables
4(a+1)-6a-(-1-5(-2a+7))=0
We add all the numbers together, and all the variables
-6a+4(a+1)-(-1-5(-2a+7))=0
We multiply parentheses
-6a+4a-(-1-5(-2a+7))+4=0
We calculate terms in parentheses: -(-1-5(-2a+7)), so:
-1-5(-2a+7)
determiningTheFunctionDomain -5(-2a+7)-1
We multiply parentheses
10a-35-1
We add all the numbers together, and all the variables
10a-36
Back to the equation:
-(10a-36)
We add all the numbers together, and all the variables
-2a-(10a-36)+4=0
We get rid of parentheses
-2a-10a+36+4=0
We add all the numbers together, and all the variables
-12a+40=0
We move all terms containing a to the left, all other terms to the right
-12a=-40
a=-40/-12
a=3+1/3

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