5(r-1)=2(r-4))-6

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Solution for 5(r-1)=2(r-4))-6 equation: 



5(r-1)=2(r-4))-6

We move all terms to the left:

5(r-1)-(2(r-4))-6)=0

We add all the numbers together, and all the variables

5(r-1)-(2(r-4))=0

We multiply parentheses

5r-(2(r-4))-5=0



We calculate terms in parentheses: -(2(r-4)), so:

2(r-4)

We multiply parentheses

2r-8

Back to the equation:

-(2r-8)



We get rid of parentheses

5r-2r+8-5=0

We add all the numbers together, and all the variables

3r+3=0

We move all terms containing r to the left, all other terms to the right

3r=-3

r=-3/3

r=-1

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