4(1+4k)=5(3k-2)

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Solution for 4(1+4k)=5(3k-2) equation: 



4(1+4k)=5(3k-2)

We move all terms to the left:

4(1+4k)-(5(3k-2))=0

We add all the numbers together, and all the variables

4(4k+1)-(5(3k-2))=0

We multiply parentheses

16k-(5(3k-2))+4=0



We calculate terms in parentheses: -(5(3k-2)), so:

5(3k-2)

We multiply parentheses

15k-10

Back to the equation:

-(15k-10)



We get rid of parentheses

16k-15k+10+4=0

We add all the numbers together, and all the variables

k+14=0

We move all terms containing k to the left, all other terms to the right

k=-14

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