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2x+1/3x=91
We move all terms to the left:
2x+1/3x-(91)=0
Domain of the equation: 3x!=0We multiply all the terms by the denominator
x!=0/3
x!=0
x∈R
2x*3x-91*3x+1=0
Wy multiply elements
6x^2-273x+1=0
a = 6; b = -273; c = +1;
Δ = b2-4ac
Δ = -2732-4·6·1
Δ = 74505
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-273)-\sqrt{74505}}{2*6}=\frac{273-\sqrt{74505}}{12} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-273)+\sqrt{74505}}{2*6}=\frac{273+\sqrt{74505}}{12} $
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