4(1+2a)+3a=48

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Solution for 4(1+2a)+3a=48 equation: 



4(1+2a)+3a=48

We move all terms to the left:

4(1+2a)+3a-(48)=0

We add all the numbers together, and all the variables

4(2a+1)+3a-48=0

We add all the numbers together, and all the variables

3a+4(2a+1)-48=0

We multiply parentheses

3a+8a+4-48=0

We add all the numbers together, and all the variables

11a-44=0

We move all terms containing a to the left, all other terms to the right

11a=44

a=44/11

a=4

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