9(r+3)=-9(r-3)+2r

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Solution for 9(r+3)=-9(r-3)+2r equation: 



9(r+3)=-9(r-3)+2r

We move all terms to the left:

9(r+3)-(-9(r-3)+2r)=0

We multiply parentheses

9r-(-9(r-3)+2r)+27=0



We calculate terms in parentheses: -(-9(r-3)+2r), so:

-9(r-3)+2r

We add all the numbers together, and all the variables

2r-9(r-3)

We multiply parentheses

2r-9r+27

We add all the numbers together, and all the variables

-7r+27

Back to the equation:

-(-7r+27)



We get rid of parentheses

9r+7r-27+27=0

We add all the numbers together, and all the variables

16r=0

r=0/16

r=0

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