4(-6)+12=3y

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Solution for 4(-6)+12=3y equation:



4(-6)+12=3y
We move all terms to the left:
4(-6)+12-(3y)=0
We add all the numbers together, and all the variables
-3y-12=0
We move all terms containing y to the left, all other terms to the right
-3y=12
y=12/-3
y=-4

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