4n-5(n+2)=11

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Solution for 4n-5(n+2)=11 equation:



4n-5(n+2)=11
We move all terms to the left:
4n-5(n+2)-(11)=0
We multiply parentheses
4n-5n-10-11=0
We add all the numbers together, and all the variables
-1n-21=0
We move all terms containing n to the left, all other terms to the right
-n=21
n=21/-1
n=-21

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