4(-4-b)=3(-3b+8)

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Solution for 4(-4-b)=3(-3b+8) equation: 



4(-4-b)=3(-3b+8)

We move all terms to the left:

4(-4-b)-(3(-3b+8))=0

We add all the numbers together, and all the variables

4(-1b-4)-(3(-3b+8))=0

We multiply parentheses

-4b-(3(-3b+8))-16=0



We calculate terms in parentheses: -(3(-3b+8)), so:

3(-3b+8)

We multiply parentheses

-9b+24

Back to the equation:

-(-9b+24)



We get rid of parentheses

-4b+9b-24-16=0

We add all the numbers together, and all the variables

5b-40=0

We move all terms containing b to the left, all other terms to the right

5b=40

b=40/5

b=8

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