-3(1+3m)+6m=-(m-7)

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Solution for -3(1+3m)+6m=-(m-7) equation: 



-3(1+3m)+6m=-(m-7)

We move all terms to the left:

-3(1+3m)+6m-(-(m-7))=0

We add all the numbers together, and all the variables

-3(3m+1)+6m-(-(m-7))=0

We add all the numbers together, and all the variables

6m-3(3m+1)-(-(m-7))=0

We multiply parentheses

6m-9m-(-(m-7))-3=0



We calculate terms in parentheses: -(-(m-7)), so:

-(m-7)

We get rid of parentheses

-m+7

We add all the numbers together, and all the variables

-1m+7

Back to the equation:

-(-1m+7)



We add all the numbers together, and all the variables

-3m-(-1m+7)-3=0

We get rid of parentheses

-3m+1m-7-3=0

We add all the numbers together, and all the variables

-2m-10=0

We move all terms containing m to the left, all other terms to the right

-2m=10

m=10/-2

m=-5

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