4(-12+6z)=48

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Solution for 4(-12+6z)=48 equation: 



4(-12+6z)=48

We move all terms to the left:

4(-12+6z)-(48)=0

We add all the numbers together, and all the variables

4(6z-12)-48=0

We multiply parentheses

24z-48-48=0

We add all the numbers together, and all the variables

24z-96=0

We move all terms containing z to the left, all other terms to the right

24z=96

z=96/24

z=4

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