(x+4)(x+4)=162

Solution for (x+4)(x+4)=162 equation:

(x+4)(x+4)=162

We move all terms to the left:

(x+4)(x+4)-(162)=0

We multiply parentheses ..

(+x^2+4x+4x+16)-162=0

We get rid of parentheses

x^2+4x+4x+16-162=0

We add all the numbers together, and all the variables

x^2+8x-146=0

a = 1; b = 8; c = -146;
Δ = b2-4ac
Δ = 82-4·1·(-146)
Δ = 648
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{648}=\sqrt{324*2}=\sqrt{324}*\sqrt{2}=18\sqrt{2}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-18\sqrt{2}}{2*1}=\frac{-8-18\sqrt{2}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+18\sqrt{2}}{2*1}=\frac{-8+18\sqrt{2}}{2}
$