4(-10-2x)+20=-36

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Solution for 4(-10-2x)+20=-36 equation: 



4(-10-2x)+20=-36

We move all terms to the left:

4(-10-2x)+20-(-36)=0

We add all the numbers together, and all the variables

4(-2x-10)+20-(-36)=0

We add all the numbers together, and all the variables

4(-2x-10)+56=0

We multiply parentheses

-8x-40+56=0

We add all the numbers together, and all the variables

-8x+16=0

We move all terms containing x to the left, all other terms to the right

-8x=-16

x=-16/-8

x=+2

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