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3x/x+x/6=11/2
We move all terms to the left:
3x/x+x/6-(11/2)=0
Domain of the equation: x!=0We add all the numbers together, and all the variables
x∈R
3x/x+x/6-(+11/2)=0
We get rid of parentheses
3x/x+x/6-11/2=0
We calculate fractions
4x^2/24x+72x/24x+(-396x)/24x=0
We multiply all the terms by the denominator
4x^2+72x+(-396x)=0
We get rid of parentheses
4x^2+72x-396x=0
We add all the numbers together, and all the variables
4x^2-324x=0
a = 4; b = -324; c = 0;
Δ = b2-4ac
Δ = -3242-4·4·0
Δ = 104976
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{104976}=324$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-324)-324}{2*4}=\frac{0}{8} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-324)+324}{2*4}=\frac{648}{8} =81 $
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